I am so bad when it comes to mathI I think I am slow! okay so my question is :
a recrusive sequence is defined by tn= 2tn-1, where t1= 5
define the first five terms of this sequnce:
so would I go like this to figure them out:
2tn-1, where t1= 5
so
2(5)(1-1)= 0
so the frist 5 are: 0, 10, 20, 30,40
am I correct or am I doing it horribley wrong?
okay there is a part b!
it says would the points of the sequence, (n,Tn), lie on the graph of an exponentail function, linear function or neithr?
I would have to say neither
am I wrong?
You have tn = 2tn-1 - 1, where t1= 5
I think your second term is wrong.
t2 = 2t1 - 1 =2*5-1 = 9
t3 = 2t2 - 1 =2*9-1 = 17
t4 = 2t3 - 1 =2*17-1 = 33
You're not "horribly" wrong, but you probably just need to see how to get started.
The fist few points look like
n Tn
1
okay now can anyone hellp me too
i also need help
5
2 9
3 17
4 33
As for part b, to determine if the points of the sequence (n, Tn) lie on the graph of an exponential or linear function, you can examine the pattern in the values. In this case, you can see that each term is obtained by multiplying the previous term by 2 and subtracting 1. This suggests that the sequence does not follow the pattern of either an exponential or linear function. Therefore, you are correct in saying that the points of the sequence do not lie on the graph of either type of function.