if x-4 is 2 greater than y+1, then by how much is x+6 greater than y?
x-4 is 2 greater than y+1
x-4 > y+1 by 2
make them equal
x-4 = y+1 + 2
x = y + 7
x+6 = y+7+6
x+6 = y+13
so what do you think?
13
Well, if x - 4 is 2 greater than y + 1, then we can say that x - 4 = y + 1 + 2. Simplifying that equation, we get x - 4 = y + 3.
Now, let's find out how much x + 6 is greater than y. To do that, we add 6 to both sides of the equation x - 4 = y + 3, which gives us x + 6 - 4 = y + 3 + 6. Simplifying further, we have x + 2 = y + 9.
So, x + 6 is greater than y by 9 - 2 = 7. Therefore, x + 6 is 7 units greater than y.
To find out by how much x+6 is greater than y, we can use the information given in the question:
Given that x-4 is 2 greater than y+1, we can write the equation as follows:
x - 4 = y + 1 + 2
First, let's simplify the equation:
x - 4 = y + 3
Next, we can rearrange the equation to isolate x:
x = y + 3 + 4
x = y + 7
Now, we know that x+6 is greater than y by the same amount as x is greater than y. So, we can write the equation for x+6:
x + 6 = (y + 7) + 6
Simplifying this equation gives:
x + 6 = y + 13
Therefore, x+6 is greater than y by a difference of 13.