Basically as you know the electrons circle the nucleus well in that first ring how many elcetrons are there, in the second and so forth

Question

Basically as you know the electrons circle the nucleus well in that first ring how many elcetrons are there, in the second and so forth

Here are the "ring" number, when filled:

2n^2 where n is the ring number:
example n= 3, the third" ring"
2*3^2= 18

No, I AM SAYING LIKE HOW MANY GO ON EACH RING, SAY FOR INSTANCE YOU A HAS OXYGEN WITH EIGHT ELECTRONS ON THE FIRST RING DO YOU RPUT TWO ELECTRONS, ON TEH SECOND DO YOU PUT FOUR, AND ON THE THRID DO YOU PUT 2, LIKE ARE THERE REQUIREMENTS

Re-read what Bob Pursley wrote. The number of electrons in each ring, when filled, is 2N^2. So for N = 1 there can be no more than 2*1^2 = 2*1 = 2 electrons. So for oxygen you place two of the 8 electrons there. That leaves six to go. They must go in the second or third shell. The second ring, N=2, can hold 2N^2 = 2*2^2 = 2*4 = 8. How many do we have? Just six, so those six go in N = 2. There are some other rules and suborbits that define placement of electrons a little better but this is the best we can do when we deal with the major "rings" or shells.

Answer 1

In the case of oxygen, with 8 electrons, you would first fill the first ring with 2 electrons. That leaves 6 electrons to distribute among the higher energy rings. The second ring, also known as the second shell, can hold a maximum of 8 electrons. So, you would place the remaining 6 electrons in the second ring. There is no specific requirement for how many electrons go in each ring, but there is a maximum number allowed based on the 2N^2 rule, where N is the ring number.