physics

A rocket is fired at a speed of 75.0 m/s from ground level, at an angle of 64.7¡ã above the horizontal. The rocket is fired toward an 11.0 m high wall, which is located 25.0 m away. The rocket attains its launch speed in a negligibly short period of time, after which its engines shut down and the rocket coasts. By how much does the rocket clear the top of the wall?

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  1. Horizontal
    distance=horzvelocity*time
    time= distance/velocity= 25/(75cos64.7)
    figure time, then put it here.
    Vertical:
    h=75*sin64.7t-4.9t^2
    how much higher is h than 11 m.

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    bobpursley
  2. thanks

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  3. where does the 4.9 come from?

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  4. h=49.62m
    49.62m-11m for the wall
    clear of the top = 38.62

    4.9 its from multiplying 1/2(-9.8m/s^2)
    1/2(ay)

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