What is the frequency of a photon with an energy of 7.40 10-18 J? (The speed of light in a vacuum is 2.998 108 m/s. Planck's constant is 6.626 10-34 J·s.)
You may have got this question in a chem glass, but it is really about physics.
E = h*frequency is the equation to use
h is Planck's constant, which you were given.
Solve for the frequency, in s^-1 (also called Hz)
You don't need to use the speed of light to answer this question. You would need that for the wavelength.
To find the frequency of a photon given its energy, you can use the formula:
E = hf
Where:
E is the energy of the photon,
h is Planck's constant, and
f is the frequency of the photon.
First, rearrange the formula to solve for frequency:
f = E/h
Now, substitute the given values into the formula:
E = 7.40 * 10^(-18) J (the energy of the photon)
h = 6.626 * 10^(-34) J·s (Planck's constant)
Therefore,
f = (7.40 * 10^(-18) J) / (6.626 * 10^(-34) J·s)
To simplify this, divide the numerator by the denominator:
f = (7.40 / 6.626) * (10^(-18) J / 10^(-34) J·s)
The division of the numbers is:
f = 1.117 * 10^16 J·s / J
Finally, express the result in the simplified form:
f = 1.117 * 10^(16) s^(-1)
So, the frequency of the photon with an energy of 7.40 * 10^(-18) J is 1.117 * 10^(16) s^(-1).