Determine the mass of zinc sulphide, Zns which is produced when 6.2 g of zinc and 4.5 g of sulphur are reacted.
My answer was 9.26 grams of zinc sulphide are produced. I wanted to verify if this was right. Please let me know. Thanks.
9.24 g ZnS is correct.
how can I get that 9.26grams of zn s?
To determine the mass of zinc sulfide (ZnS) produced when 6.2 g of zinc (Zn) and 4.5 g of sulfur (S) are reacted, we need to calculate the theoretical yield of the reaction.
The reaction equation is:
Zn + S ⟶ ZnS
To find the mass of zinc sulfide produced, we need to determine the limiting reactant. The limiting reactant is the reactant that is completely consumed in the reaction and limits the amount of product formed.
To determine the limiting reactant, we need to compare the moles of zinc and sulfur available for the reaction. The balanced equation tells us that 1 mole of zinc reacts with 1 mole of sulfur to produce 1 mole of zinc sulfide.
Converting the masses of zinc and sulfur to moles:
Molar mass of zinc (Zn) = 65.38 g/mol
Molar mass of sulfur (S) = 32.07 g/mol
Moles of zinc (Zn) = mass of zinc (g) / molar mass of zinc
= 6.2 g / 65.38 g/mol
≈ 0.095 moles
Moles of sulfur (S) = mass of sulfur (g) / molar mass of sulfur
= 4.5 g / 32.07 g/mol
≈ 0.140 moles
From the balanced equation, we can see that 1 mole of zinc reacts with 1 mole of sulfur to produce 1 mole of zinc sulfide. Therefore, the stoichiometric ratio tells us that the same number of moles of reactants will be consumed and produced.
Comparing the moles of zinc and sulfur, we see that the mole ratio is approximately 0.095:0.140. This indicates that there is an excess of sulfur.
To determine the mass of zinc sulfide produced, calculate the mass of zinc sulfide that can be formed from the limiting reactant, which is zinc in this case.
Molar mass of zinc sulfide (ZnS) = 97.44 g/mol
Moles of zinc sulfide (ZnS) = moles of limiting reactant (Zn)
Mass of zinc sulfide (ZnS) = moles of zinc sulfide (ZnS) × molar mass of zinc sulfide
Mass of zinc sulfide (ZnS) = 0.095 moles × 97.44 g/mol
≈ 9.19 g
Therefore, the mass of zinc sulfide (ZnS) produced when 6.2 g of zinc and 4.5 g of sulfur are reacted is approximately 9.19 grams, not 9.26 grams.
Please note that this is the theoretical yield, and the actual yield may be lower due to various factors such as incomplete reactions or side reactions.