8 Zn + S8 --> 8 ZnS
if 5.00 g of zinc and 3.00g of S8 are available what is ZnS mass?
This is a limiting reagent problem (LR). You know that when amounts are given for more than one of the reactants.
Step 1. Write and balance the equation. You've done that.
Step 2. Determine if Zn or S8 is the LR. There is a short way and a long way. I'll show you the long way.
2. Determine moles each reactant. I will round numbers so you may want to go back and recalculate more accurately.
2a. moles Zn = grams atomic mass = 5.00/about 65 = 0.077
2b. moles S8 = 3.00/256 = 0.012
3. Calculate moles of the product formed for EACH reactant.
3a. First Zn. 0.077 mols Zn x (8 moles ZnS/8 moles Zn) = 0.077 x 1 = 0.077
3b. next S8. 0.012 moles S8 x (8 moles ZnS/1 mol S8) = 0.012 x 8 = 0.096
3c. Identify the LR which is Zn since that produces the smaller of the two reactants.
4. Convert mols Zn to grams. 0.077 x molar mass ZnS = 0.077 x 97 = 7.5 g.
Remember that I have rounded so that 7.5 g is approximate.
To determine the mass of ZnS produced, we need to follow a few steps.
Step 1: Calculate the number of moles of zinc (Zn) and sulfur (S8) using their respective molar masses.
The molar mass of Zn is 65.38 g/mol.
The molar mass of S8 is 256.52 g/mol.
Number of moles of Zn = mass of Zn (g) / molar mass of Zn
= 5.00 g / 65.38 g/mol
Number of moles of S8 = mass of S8 (g) / molar mass of S8
= 3.00 g / 256.52 g/mol
Step 2: Determine the limiting reactant.
To determine which reactant is limiting, we compare the moles of each reactant to the stoichiometric ratio provided by the balanced equation. From the balanced equation, we can see that the ratio of Zn to S8 is 8:1.
Ratio of moles of Zn to moles of S8 = 8
If the ratio of moles of Zn to moles of S8 is greater than 8, then S8 is the limiting reactant. If the ratio is less than 8, then Zn is the limiting reactant.
Step 3: Calculate the moles of ZnS formed using the limiting reactant.
If Zn is the limiting reactant, all the Zn (in moles) will react with S8 to form ZnS. Therefore, the moles of ZnS formed would be equal to the moles of Zn.
If S8 is the limiting reactant, we need to determine the moles of ZnS formed using the stoichiometric ratio provided by the balanced equation. From the balanced equation, we can see that 8 moles of ZnS are formed from 1 mole of S8.
Moles of ZnS formed = moles of S8 (if S8 is limiting) x 8.
Step 4: Calculate the mass of ZnS formed.
Mass of ZnS formed = moles of ZnS formed x molar mass of ZnS.
The molar mass of ZnS is the sum of the molar masses of zinc (Zn) and sulfur (S) in ZnS, which are 65.38 g/mol and 32.06 g/mol, respectively.
Now, you can plug in the calculated values into the equation and solve for the mass of ZnS formed.
To find the mass of ZnS produced, we need to determine the limiting reactant first. The limiting reactant is the reactant that is completely consumed and determines the maximum amount of product that can be formed.
Let's start by calculating the moles of each reactant:
Molar mass of zinc (Zn) = 65.38 g/mol
Moles of Zn = mass of Zn / molar mass of Zn
Moles of Zn = 5.00 g / 65.38 g/mol
Molar mass of sulfur (S8) = 256.52 g/mol
Moles of S8 = mass of S8 / molar mass of S8
Moles of S8 = 3.00 g / 256.52 g/mol
Next, we need to determine the stoichiometric ratio between Zn and ZnS from the balanced equation. We can see that for every 8 moles of Zn, 8 moles of ZnS are produced:
Stoichiometric ratio: 8 moles of Zn : 8 moles of ZnS
Now, let's compare the moles of Zn and S8 to determine the limiting reactant:
Moles of ZnS produced = Moles of limiting reactant * Stoichiometric ratio
If the moles of Zn are lower than the moles of S8, Zn is the limiting reactant, and vice versa.
Finally, we can calculate the mass of ZnS produced using the moles of ZnS and the molar mass of ZnS:
Molar mass of zinc sulfide (ZnS) = 97.45 g/mol
Mass of ZnS = Moles of ZnS * Molar mass of ZnS
Follow these steps to find the mass of ZnS produced.