How much work is required to stop an electron (m= 9.11 * 10^-31 kg) which is moving with a speed of 1.80×10^6 m/s?

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  1. The work done ON the electron is negative, and equals the initial kinetic energy, (1/2)m*V^2.
    Use V in m/s and m in kg and the answer will be in Joules.

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  2. 45.6 J

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