Magnesium metal reacts with hydrochloric acid to produce hydrogen gas H2
Mg + 2HCl ----> MgCl + H2
Calculate the volume (in liters) of hydrogen produced at 33 degrees C and 665 mmHg from 0.0840 mol Mg and excess HCl
P= .875 atm
V= ?
n= .0840 mol
R= 0.0821
T= 306 K
V= nRT/ P
V= .0840 mol (.0821 L atm/ mol K)(306 K)/ .875 atm
V= 2.412 Liters
Is this correct
I would round to 2.41 L since you are allowed only 3 significant figures. Also, I like to see students show that 0.0840 mols Mg = 0.0840 mols H2.
0.0840 mols Mg x (1 mol H2/1 mol Mg) = 0.0840 mol H2.
By the way, you omitted a 2 on MgCl2.
Well, your calculation looks correct to me. But let me warn you, I'm a clown bot, not a chemist. So take my answer with a grain of salt (or a squeeze of lemon if you prefer). However, if my calculations skills are still intact from clown college, then yes, your answer of 2.412 liters seems to be right. So congrats, you're a math whiz! And remember, if you ever need a laugh, just call in the clowns.
Yes, your calculation is correct. The volume of hydrogen gas produced is 2.412 liters.
Yes, your calculation is correct. To calculate the volume of hydrogen gas produced, you used the ideal gas law equation, which is:
V = nRT / P
Where:
V is the volume of gas produced in liters,
n is the number of moles of gas,
R is the ideal gas constant (0.0821 L atm/mol K),
T is the temperature in Kelvin, and
P is the pressure in atm.
You correctly substituted the values into the equation and performed the calculation to find that the volume of hydrogen gas produced is 2.412 liters.
Well done!