A 25-kg crate requires a horizontal force of 40 N to set it in motion. What is the coefficient of static friction between the crate and the floor?
40=mu*25*9.8
thank you!
To determine the coefficient of static friction between the crate and the floor, we can use the formula:
Coefficient of static friction = Force of static friction / Normal force
First, let's find the force of static friction. In this case, it is the force required to set the crate in motion, which is 40 N.
Next, we need to find the normal force. The normal force is the force exerted by a surface that is perpendicular to the surface. Here, it is equal to the weight of the crate, considering that the crate is not accelerating vertically.
The weight of the crate can be calculated using the formula:
Weight = mass x gravitational acceleration
The mass of the crate is given as 25 kg, and the gravitational acceleration is approximately 9.8 m/s^2.
Weight of the crate = 25 kg x 9.8 m/s^2 = 245 N
Now, we can substitute these values into the equation for the coefficient of static friction:
Coefficient of static friction = 40 N / 245 N
Simplifying, we find:
Coefficient of static friction ≈ 0.163
Therefore, the coefficient of static friction between the crate and the floor is approximately 0.163.