the length of a rectangular jewlery box is 6 inches more than twice the width. the perimeter is 54 inches find length and width.
i want the answer not to solve it
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To find the length and width of the rectangular jewelry box, we can use two equations:
1. The length of the box is 6 inches more than twice the width: Length = 2*width + 6
2. The perimeter of a rectangle is given by the formula: Perimeter = 2*Length + 2*Width
Given that the perimeter is 54 inches, we can substitute the values into equation 2:
54 = 2*(2*width + 6) + 2*width
Now we can solve this equation to find the value of the width:
54 = 4*width + 12 + 2*width
54 = 6*width + 12
6*width = 54 - 12
6*width = 42
width = 42/6
width = 7 inches
Now that we have the width, we can substitute this value into equation 1 to find the length:
Length = 2*width + 6
Length = 2*7 + 6
Length = 14 + 6
Length = 20 inches
Therefore, the length of the rectangular jewelry box is 20 inches and the width is 7 inches.
Solve the following:
L = 2W + 6
2(L + W) = 54
Rewrite them as:
2W + 2L = 54
2W - L = -6
Subtract the last equation from the third equation. You get an equation in L only.
3L = 60.
Take it from there.