The electrolysis (decomposition) of water produces hydrogen gas at the rate of 30.0 mL/min.
A) Write a balanced chemical equation for this reaction and include phase designations.
2H2O(aq)---> 4H2(g)O2(g)
Is whatever I've done above correct?
B) What volume of hydrogen gas can be produced in 4.5 min?
30.0 ml
_______ = 66.6v.
4.5 min
Is this right?
C) Based on your balanced equation, predict the rate of oxygen gas produced.
I am unsure of this question. I don't get it.
A looks ok but you omitted the + sign between the products.
B doesn't look right to me. The units don't seem to be right. I would think if the production is 30 mL/min then it would be 30 mL/min x 4.5 min (note the min calcel to leave mL which is what you want) = 30 x 4.5 = ??
C. Looking at the coefficients, I would think O2 would be produced at 1/4 the rate of H2 since the coefficients are 4/1 in favor of hydrogen.
A) The balanced chemical equation for the electrolysis (decomposition) of water is:
2H2O(l) → 4H2(g) + 2O2(g)
Note that (aq) indicates that water is in the liquid state, while (g) indicates that hydrogen and oxygen gases are produced.
Your answer is almost correct, but you forgot to include the phase designation for oxygen. It should be:
2H2O(aq) → 4H2(g) + O2(g)
B) To calculate the volume of hydrogen gas produced in 4.5 minutes, we can use the given rate of 30.0 mL/min. This rate tells us that for every minute, 30.0 mL of hydrogen gas is produced.
To find the volume produced in 4.5 minutes, we can multiply the rate by the time:
Volume = Rate × Time
Volume = 30.0 mL/min × 4.5 min
Volume = 135.0 mL
Therefore, the volume of hydrogen gas produced in 4.5 minutes is 135.0 mL.
Your answer is incorrect. To correctly calculate it, we need to multiply the rate (30.0 mL/min) by the time (4.5 min). So, it should be:
Volume = 30.0 mL/min × 4.5 min = 135.0 mL
C) Based on the balanced equation 2H2O(l) → 4H2(g) + O2(g), we can see that for every 2 moles of water decomposed, 1 mole of oxygen gas is produced. Therefore, the rate of oxygen gas production would be half the rate of hydrogen gas production.
Since the rate of hydrogen gas production is 30.0 mL/min, the rate of oxygen gas production would be:
Rate of Oxygen Gas Production = 0.5 × Rate of Hydrogen Gas Production
Rate of Oxygen Gas Production = 0.5 × 30.0 mL/min
Rate of Oxygen Gas Production = 15.0 mL/min
Therefore, the predicted rate of oxygen gas produced is 15.0 mL/min.