solve
-16t^2 +64t+6 the value of t is 2
-16(2)^2+64(2)+6=
-16(4)+128+6=
-64+128+6=
To solve the equation -16t^2 + 64t + 6 = 0 when the value of t is 2, we can substitute t = 2 into the equation and see if it satisfies the equation.
Replace t with 2 in the equation:
-16(2)^2 + 64(2) + 6 = 0
Simplifying this:
-16(4) + 128 + 6 = 0
-64 + 128 + 6 = 0
70 = 0
Since 70 does not equal 0, the value of t = 2 does not satisfy the equation. Therefore, the value of t = 2 is not a solution to the equation -16t^2 + 64t + 6 = 0.