math

find the equation of the circle passing through (-1,2)(2,6)(6,3)

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asked by Kim
  1. A general equation could be written:
    (x-a)^2 + (y-b)^2 = c^2
    where c is the radius of the circle.
    You can use the coordinates of the three given points to get three equations in three unknowns.
    (-1-a)^2 + (2-b)^2 = c^2
    (2-a)^2 + (6-b)^2 = c^2
    (6-a)^2 + (3-b)^2 = c^2
    Then solve for a, b and c

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    posted by drwls

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