how do I solve the equation (y+6) divided by 3- (y-3) divided by2=2
[(y+6)/3] - [(y-3)/2] = 2
Is it the prob?
If so, it will be
(y+6)2 - (y-3)3 = 2*3*2
2y+12 - (3y-9) =12
2y +12 -3y +9 =12
-y = -9
y = 9
To solve the equation ((y + 6) / 3) - ((y - 3) / 2) = 2, follow these steps:
Step 1: Remove the parentheses.
The equation becomes (y + 6) / 3 - (y - 3) / 2 = 2.
Step 2: Find a common denominator.
The two fractions on either side of the equation have different denominators, 3 and 2. To solve this, we need to find the least common multiple (LCM) of 3 and 2, which is 6. Multiply the numerator and denominator of the first fraction by 2, and the numerator and denominator of the second fraction by 3.
The equation now becomes: (2(y + 6) / 6) - (3(y - 3) / 6) = 2.
Step 3: Simplify the equation.
Distribute the numerators on the fractions:
(2y + 12) / 6 - (3y - 9) / 6 = 2.
Combine the fractions:
(2y + 12 - 3y + 9) / 6 = 2.
Combine like terms:
(-y + 21) / 6 = 2.
Step 4: Isolate the variable.
Multiply both sides of the equation by 6 to eliminate the denominator:
- y + 21 = 12.
Step 5: Solve for y.
To isolate y, subtract 21 from both sides of the equation:
- y = 12 - 21.
Simplify:
- y = -9.
Finally, multiply both sides of the equation by -1 to solve for y:
y = 9.
Therefore, the solution to the equation is y = 9.