Three times the greastest of three consecutive even integers exceeds twice the least by 38. Find the integers.
This is a duplicate of the one i just solved.
To solve this problem, let's assume that the three consecutive even integers can be represented as x, x+2, and x+4.
According to the problem, three times the greatest of the three consecutive even integers exceeds twice the least by 38. This can be translated into the following equation:
3(x+4) = 2x + 38
Now, let's solve this equation step by step:
First, distribute the 3 to both terms inside the parentheses:
3x + 12 = 2x + 38
Next, combine like terms by moving all the terms involving x to one side of the equation:
3x - 2x = 38 - 12
Simplifying further:
x = 26
Now that we have found the value of x, we can find the three consecutive even integers:
The first even integer = x = 26
The second even integer = x + 2 = 26 + 2 = 28
The third even integer = x + 4 = 26 + 4 = 30
So, the three consecutive even integers are 26, 28, and 30.