Perform the indicated operation and the write the result in standard form
(6+ sq root -5)(6 + sq root -7)=
(1 + square root)(-1 + square root)
is the answer 0? don't they cancel out?
could you help with my algebra question?
Do this with FOIL. I will be happy to check your work.
okay I got 1-12 sq root of 35i is this correct
6*6 + 6isqrt7 +5i*sqrt5+ i*sqrt35
I don't see how you can get less than four terms.
Well that isnt one of my answers the question is multiple choice another choice is (36 - sq rt 35) + (6 sqrt 7 + 6 sqrt 5)i
Other than a small typo, bobpursley is right
He meant to say:
6*6 + 6isqrt7 +5i*sqrt5+ i^2*sqrt35
= 36 + 6i√7 + 5i√5 - √35
George, trust us, we are right according to the way you typed the question!
To perform the indicated operation and write the result in standard form, we will follow these steps:
Step 1: Simplify each square root term individually.
Step 2: Multiply the simplified terms using the FOIL method.
Step 3: Combine any like terms.
Step 4: Write the final answer in standard form.
Let's start with step 1:
Simplifying square root(-5):
To simplify √(-5), we can recall that the square root of a negative number is not a real number. However, we can express it using the imaginary unit "i" such that √(-5) = √(5) * i.
Simplifying square root(-7):
Using the same logic as before, we simplify √(-7) as √(7) * i.
Now, let's move on to step 2:
Multiplying the simplified terms using FOIL:
(6 + √5 * i)(6 + √7 * i)
Using the FOIL method, we have:
6 * 6 + 6 * √7 * i + 6 * √5 * i + √5 * i * √7 * i
Simplifying the products of the square roots:
√5 * i * √7 * i can be rewritten as √(5 * 7) * i * i. Since i * i is equal to -1, it becomes √(5 * 7) * -1, which simplifies to -√35.
Combining like terms:
36 + 6√7 * i + 6√5 * i - √35
Now, let's move on to step 4:
Writing the final answer in standard form:
The final result is 36 + 6√7 * i + 6√5 * i - √35, which cannot be simplified further.
So, the result in standard form is 36 + 6√7 * i + 6√5 * i - √35.