Determine whether the integral converges or diverges. Find the value of the integral if it converges.
The integral where b=2 and a=0 (x/x^2-1 dx).
For ∫ xdx/(x²-1) from 0 to 2, we have to note that there is a vertical asymptote in the function at x=1, hence divide the range of integration into two parts, namely 0 to 1 and 1 to 2 and integrate accordingly.
If each sub-integral exists and is convergent, the answer is the sum of the two. Otherwise, the original integral is divergent.