in a experiment to detrmine the acceleration of free fall 'g' a student attached a length of ticker tape to a metal ball. when the ball was released it fell to the ground pulling the tape through a ticker timer that printed 50 dots per second on the tape. the student measured lengths of tape to find the speed ofthe ball as it fell.
a. calculate the time taken for the timer to print 10 dots on the tape.
b. the student cut the tape into lengths with 10 dots each, starting at the end attached to the ball. would you expect the lenghts to increase,decrease or stay the same as the ball fell?
a. To calculate the time taken for the timer to print 10 dots on the tape, we can use the given information about the ticker timer's printing rate.
The ticker timer prints 50 dots per second on the tape. Therefore, the time it takes to print 10 dots can be calculated by dividing the number of dots (10) by the printing rate (50 dots/second):
10 dots / (50 dots/second) = 0.2 seconds
So, it would take the timer 0.2 seconds to print 10 dots on the tape.
b. When the student cuts the tape into lengths with 10 dots each, starting at the end attached to the ball, we would expect the lengths to decrease as the ball fell.
This is because the tape is being pulled through the ticker timer at a constant rate of 50 dots per second. As the ball falls, it gains speed and accelerates due to gravity. This means that the rate at which the tape is pulled through the timer increases, resulting in fewer dots being printed on each successive length of tape.
Therefore, the lengths of tape with 10 dots each would decrease as the ball falls.