what substance is oxidized in following reaction 4 HCl+MnO2 and Cl2+2H2O+MnCl2

Oxidation is the loss of electrons.

Mn goes from +4 on the left to +2 on the right.
Cl goes from -1 on the left to 0 on the right.

To determine which substance is oxidized in the given reaction, we need to identify the changes in oxidation numbers for each element.

Let's start by assigning oxidation numbers to the elements in the equation:

Oxidation number of H in HCl: +1
Oxidation number of Cl in HCl: -1
Oxidation number of Mn in MnO2: +4
Oxidation number of O in MnO2: -2
Oxidation number of Cl in Cl2: 0
Oxidation number of H in H2O: +1
Oxidation number of O in H2O: -2
Oxidation number of Mn in MnCl2: +2
Oxidation number of Cl in MnCl2: -1

Now, let's analyze the changes in oxidation numbers for each element:

1. Hydrogen (H): The oxidation number of H changes from +1 in HCl to +1 in H2O. There is no change in the oxidation number of H.

2. Chlorine (Cl): The oxidation number of Cl changes from -1 in HCl to 0 in Cl2 or 0 in MnCl2. This indicates that Cl is oxidized from -1 to 0.

3. Manganese (Mn): The oxidation number of Mn changes from +4 in MnO2 to +2 in MnCl2. This indicates that Mn is reduced from +4 to +2.

Based on the changes in oxidation numbers, we can conclude that chlorine (Cl) is oxidized in the given reaction.

Note: Another way to identify the substance being oxidized is to look at the reactants and products. In this case, we can see that Cl2 is formed as a product, which indicates that Cl is being oxidized.

In the given reaction, 4 HCl (hydrochloric acid) and MnO2 (manganese dioxide) are the reactants, while Cl2 (chlorine gas), 2 H2O (water), and MnCl2 (manganese(II) chloride) are the products.

To identify the substance that undergoes oxidation, we need to examine the oxidation numbers of the elements involved.

In HCl, the oxidation number of hydrogen (H) is +1, and the oxidation number of chlorine (Cl) is -1.

In MnO2, the oxidation number of manganese (Mn) is +4, and the oxidation number of oxygen (O) is -2.

In Cl2, the oxidation number of chlorine (Cl) is 0.

In H2O, the oxidation number of hydrogen (H) is +1, and the oxidation number of oxygen (O) is -2.

In MnCl2, the oxidation number of manganese (Mn) is +2, and the oxidation number of chlorine (Cl) is -1.

Upon examining the reaction, we can see that the oxidation number of chlorine (Cl) changes from -1 in HCl to 0 in Cl2, indicating that chlorine is undergoing oxidation. Therefore, in the given reaction, chlorine is the substance that is oxidized.