I know I posted this yesterday but I really do not understand this and I did not quite understand the comment on what to do.
Find the real solutions of the equation.
x = 2 sqrt6x-36
To find the real solutions of the equation, we need to solve for x. The given equation is:
x = 2√(6x - 36)
To start solving, let's isolate the square root term on one side of the equation.
Step 1: Square both sides of the equation to eliminate the square root:
x^2 = (2√(6x - 36))^2
x^2 = 4(6x - 36)
Simplifying further, we get:
x^2 = 24x - 144
Step 2: Move all terms to one side of the equation to set it equal to zero:
x^2 - 24x + 144 = 0
Step 3: Factorize the quadratic equation:
(x - 12)(x - 12) = 0
Step 4: Set each factor equal to zero:
x - 12 = 0
Solving for x, we get:
x = 12
Therefore, the real solution to the equation x = 2√(6x - 36) is x = 12.