What is the work required to move a proton 1 cm along the 7 volt equipotential line?
zero. Work=charge*difference in potential
I'm not sure how this is zero?
To calculate the work required to move a proton along an equipotential line, we need to use the formula:
Work = Charge × Voltage
Here's how you can calculate it:
1. Determine the charge of a proton: The charge of a proton is equal to the elementary charge, which is approximately 1.6 × 10^-19 coulombs (C).
2. Determine the voltage: In this case, the voltage is given as 7 volts (V).
3. Multiply the charge by the voltage to find the work:
Work = (1.6 × 10^-19 C) × (7 V)
Work = 1.12 × 10^-18 Joules (J)
So, the work required to move a proton 1 cm along the 7 volt equipotential line is approximately 1.12 × 10^-18 Joules.