A number is between 150 and 200. A sum of the digits is 12. If you subtract the ones digit from the tens digit, the difference is 5. What is the number?
Let the number be ABC, which is between 150 and 200, so A=1. (minimum is 151 and maximum is 199)
A+B+C = 12
so 1+B+C=12
and B-C=5
solve to find B and C
-1/2-2/3
Please post a new question if you want your question to be seen by teachers. Do not add it as a followup to an answer to someone else's question.
When adding fractions, make sure they have a common denominator. Then you can add the numerators.
To find the number, we can use a systematic approach by trying out different possibilities within the given range of 150 to 200 and checking if they meet the given conditions.
1. Start by listing down all the numbers within the given range: 150, 151, 152, ... , 199, 200.
2. Check the sum of each number's digits to see if it adds up to 12.
Let's go through the numbers one by one:
- For 150, the sum of the digits is 1 + 5 + 0 = 6, which doesn't meet the condition of a sum of digits being 12.
- For 151, the sum of the digits is 1 + 5 + 1 = 7, which also doesn't meet the condition.
- Continue this process until we find a number that satisfies the condition.
- For 159, the sum of the digits is 1 + 5 + 9 = 15, which is not equal to 12.
- For 160, the sum of the digits is 1 + 6 + 0 = 7, which is still not equal to 12.
- We'll continue this process until we reach a number that satisfies the condition.
- For 161, the sum of the digits is 1 + 6 + 1 = 8, which is still not equal to 12.
- For 162, the sum of the digits is 1 + 6 + 2 = 9, which is still not equal to 12.
- We'll keep going until we find the number.
- Finally, for 166, the sum of the digits is 1 + 6 + 6 = 13, which is not equal to 12.
After trying all the numbers from 150 to 200, we haven't found a number that satisfies the condition of the sum of the digits being equal to 12.
Therefore, based on the given information, there is no number between 150 and 200 that meets the given conditions.