I need help setting up this problem:
Ethylene glycol has a specific gravity of 1.1088 at room temperature, What is the volume of 1.00 kg of ethylene glycol? What is the volume of 2.00 lb of ethylene glycol?
Using 25 degrees Celsius.
I apologize. Specific gravity has no units; I inadvertently read it as density. My error.
Since no temperature is specified, we must assume specific gravity to be the same as density; therefore, density = 1.1088 g/mL.
1.0 kg ethylene glycol = 1,000 grams.
mass = volume x density or
volume = mass/density = 1,000/1.1088 = ??
For the second part, convert 1 lb to grams and substitute as above.
NOTE: I see you wrote 1.1088 in the first response and 1.088 in the second one (twice). Use the correct value; whatever that number is.
.902 L
1.1088 WHAT?
There are no units after 1.088 in the problem it just says a specific gravity of 1.088 at room temperature.
To solve this problem, we need to use the concept of specific gravity, which compares the density of a substance to the density of water.
The specific gravity of ethylene glycol is given as 1.1088. This means that ethylene glycol is 1.1088 times denser than water at the same temperature.
To find the volume of 1.00 kg of ethylene glycol:
Step 1: Convert the mass from kg to grams.
1 kg = 1000 grams
Step 2: Use the formula for density:
Density = mass/volume
Rearrange the formula to solve for volume:
Volume = mass/density
Step 3: Substitute the given values into the formula.
Volume = 1000 grams / (density of ethylene glycol)
Since specific gravity compares the density to water, we can use the density of water at 25 degrees Celsius, which is 0.997 g/ml.
Volume = 1000 grams / (1.1088 * 0.997 g/ml)
To find the volume of 2.00 lb of ethylene glycol, we need to convert pounds to grams:
Step 1: Convert the mass from pounds to grams.
1 lb = 453.592 grams
Step 2: Use the formula for density:
Volume = mass/density
Step 3: Substitute the given values into the formula.
Volume = 2.00 lb * 453.592 grams / (1.1088 * 0.997 g/ml)
Simplify the equations and calculations to find the final results.