3x (x-3)^3 - x (x-3)^2
ps. I am staring at this problem for a long tym and have noo clue please help?
factor it:
x(x-3)^2 [3x-9-1]
simplify the last term, and you have it.
THANK YOU SOO MUCH!!this was my 26th review question and my brain was not functioning properly..hehe thank once again
To simplify the given expression 3x(x-3)^3 - x(x-3)^2, we can follow the order of operations (also known as PEMDAS/BODMAS) to simplify it step by step:
Step 1: Simplify the exponents within the parentheses.
(x-3)^3 can be expanded as (x-3)(x-3)(x-3) = (x-3)(x^2 - 6x + 9).
Similarly, (x-3)^2 can be expanded as (x-3)(x-3) = (x-3)(x^2 - 6x + 9).
So, the expression becomes 3x(x^2 - 6x + 9) - x(x^2 - 6x + 9).
Step 2: Distribute the terms inside both parentheses.
Multiply 3x by each term in (x^2 - 6x + 9) to get 3x^3 - 18x^2 + 27x.
Multiply -x by each term in (x^2 - 6x + 9) to get -x^3 + 6x^2 - 9x.
This simplifies the expression to 3x^3 - 18x^2 + 27x - x^3 + 6x^2 - 9x.
Step 3: Combine like terms.
3x^3 - x^3 is equal to 2x^3.
-18x^2 + 6x^2 simplifies to -12x^2.
27x - 9x simplifies to 18x.
The final simplified expression is: 2x^3 - 12x^2 + 18x.
By following these steps, we have simplified the given expression.