a coin is tossed twice and a number cube is rolled. Find probability. 1 head, 1 tail,and 3
prob of 1 head and 1 tail = (1/2)(1/2) + (1/2)(1/2) = 1/2
prob of 1 head, 1 tail, and a 3
= (1/2)(1/6) = 1/12
To find the probability of getting 1 head, 1 tail, and a 3, we need to first calculate the individual probabilities of each event, and then multiply them together.
1. Tossing a coin twice:
Since the coin has two equally likely outcomes (heads or tails), the probability of getting a head on each toss is 1/2, and the probability of getting a tail is also 1/2. As we need to get 1 head and 1 tail, we multiply the probabilities together: 1/2 * 1/2 = 1/4.
2. Rolling a number cube:
A number cube (or dice) has 6 equally likely outcomes, which are the numbers 1, 2, 3, 4, 5, and 6. The probability of rolling a 3 is 1 out of 6, or 1/6.
Now, we multiply the probabilities of the coin toss and the number cube: 1/4 * 1/6 = 1/24.
Therefore, the probability of getting 1 head, 1 tail, and a 3 is 1/24.