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A dockworker loading crates on a ship finds that a 20 kg crate, initially at rest on horizontal force to set it in motion. However, after the crate is in motion, a horizontal force of 60 N is required to keep it moving with a constant speed. Find the coeffiecints of static and kinetic friction between crate and floor.

Work:
75N=(20kg)a a=3.75m/s^2
60N=(20kg)a a=3m/s^2

I am not sure if I am starting it correctly. How would I solve this problem?

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  1. A dockworker loading crates on a ship finds that a 20 kg crate, initially at rest on horizontal surface requires a 75N horizontal force to set it in motion. However, after the crate is in motion, a horizontal force of 60 N is required to keep it moving with a constant speed. Find the coefficients of static and kinetic friction between crate and floor.

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  2. No, friction= mu*m*g
    75=mu*20*9.8 solve fro mu static
    50=mukinetic*20*9.8 solve for mu kinetic

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    👤
    bobpursley
  3. coefficient of friction = force app (F)/ Friction (9.8*20)

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  4. sda

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