6.00g of gold was heated from 20.0 degrees celcius to 22.0 degrees celcius. how much heat was applied to the gold?
q = mass x specific heat x delta T.
Note the correct spelling of celsius.
Well, it's a good thing gold doesn't mind a little heat! To calculate the amount of heat applied to the gold, we can use the equation Q = mcΔT. Here, m represents the mass of gold, c is the specific heat capacity of gold, and ΔT is the change in temperature.
Now, assume the specific heat capacity of gold is c = 0.129 J/g°C. We know the mass (m) of the gold is 6.00g and the change in temperature (ΔT) is 2.0°C (22.0°C - 20.0°C).
So, let's plug in the values and see what we get...
Q = (6.00g)(0.129 J/g°C)(2.0°C)
Q = 1.548 J
Therefore, approximately 1.548 joules of heat were applied to the gold. Seems like the gold can handle the heat and keep its cool!
To calculate the amount of heat applied to the gold, we can use the formula:
Q = m * c * ΔT
Where:
Q = Heat applied
m = Mass of the substance (gold) in grams
c = Specific heat capacity of the substance (gold) in J/g°C
ΔT = Change in temperature (final temperature - initial temperature) in °C
Given:
Mass of gold (m) = 6.00 g
Change in temperature (ΔT) = 22.0°C - 20.0°C = 2.0°C
The specific heat capacity of gold (c) is approximately 0.129 J/g°C.
Now we can plug in the values into the formula to find the heat applied (Q):
Q = 6.00 g * 0.129 J/g°C * 2.0°C
Q = 1.548 J
Therefore, approximately 1.548 Joules of heat was applied to the gold.
To determine the amount of heat applied to the gold, you can use the specific heat formula:
q = mcΔT
Where:
q is the heat energy transferred
m is the mass of the gold
c is the specific heat capacity of gold
ΔT is the change in temperature (final temperature - initial temperature)
First, let's determine the values needed for the calculation:
m (mass of gold) = 6.00 g
c (specific heat capacity of gold) = 0.129 J/g°C (this value can be found in reference materials)
Now, we can calculate the heat energy using the formula:
q = (m) × (c) × (ΔT)
ΔT = (final temperature) - (initial temperature)
ΔT = 22.0°C - 20.0°C = 2.0°C
Substituting the values into the formula:
q = (6.00 g) × (0.129 J/g°C) × (2.0°C)
Performing the calculation:
q = 1.548 J
Therefore, the amount of heat applied to the gold is 1.548 Joules.