what is the energy of a 606 nm photon emitted from a light source?
Answer in units of J.
E = hc/wavelength
606 nm must be converted to meters.
i did that. but the answer was wrong.
i got the answer to be 3.29 X 10^-19 J.
what did i do wrong ?
I have 3.28 x 10^-19 J.
I am using 6.626E-34 for h, 3 x 10^8 m/s for c and 606 x 10^-9 m for wavelength.
To find the energy of a photon, we can use the equation:
E = hc/λ
where:
E is the energy of the photon,
h is the Planck's constant (6.626 x 10^-34 J·s),
c is the speed of light in a vacuum (3.00 x 10^8 m/s),
and λ is the wavelength of the photon.
Given that the wavelength (λ) is 606 nm (or 606 x 10^-9 m), we can substitute these values into the equation and calculate the energy of the photon.
E = (6.626 x 10^-34 J·s * 3.00 x 10^8 m/s) / (606 x 10^-9 m)
E ≈ 3.28 x 10^-19 J
Therefore, the energy of a 606 nm photon emitted from a light source is approximately 3.28 x 10^-19 J.