jet stream which is flowing at a rate of 80 miles per hour. It travels with the jet stream for 5 hours and then reduces its altitude, flying out of the jet stream for 4 more hours. The plane, while out of the jet stream, covered 550 miles less than it did during the 5 hours it was in the jet stream. How fast was the plane flying out of the jet stream?
distance in stream = (v+80)5
distance out of stream = 4 v
4 v + 550 = 5(v+80)
To find the speed of the plane flying out of the jet stream, we need to break down the information provided in the problem.
Let's denote the speed of the plane flying out of the jet stream as "x" (in miles per hour).
During the 5 hours the plane was in the jet stream, it covered a distance of 5 hours * 80 miles per hour = 400 miles.
When the plane was out of the jet stream for 4 hours, it covered a distance 550 miles less than it did during the 5 hours it was in the jet stream. Therefore, the plane covered a distance of 400 miles - 550 miles = -150 miles.
However, it is not possible to travel a negative distance, so this conclusion doesn't make sense. It means there might be an error or inconsistency in the given information.
Could you please double-check the problem statement or provide any additional information if available?