Solve the quadratic equation.
12x2 + 23x + 10 = 0
A.5/4,2/3 B. 5/12, 1/5 C. 5/4, 2/3
D. 5/4, 2/3
without even working it out, I can tell your answer is wrong.
both your answers are positive, and all the terms on the left side of the equation are positive.
How can the sum of a bunch of positive numbers equal zero?
12x^2 + 23x + 10 = 0
(3x+2)(4x+5) = 0
x = -2/3 or x = -5/4
so none of the choices you gave are correct, since all of them are positive.
Sorry, I miss read the answers.I did not see the neg.
On B, C they are both negative and on D. 5/4, -2/3
To solve the quadratic equation 12x^2 + 23x + 10 = 0, we can use the quadratic formula. The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solutions for x are given by:
x = (-b ± √(b^2 - 4ac))/(2a)
Applying this formula to our quadratic equation, we have a = 12, b = 23, and c = 10. Substituting these values into the quadratic formula, we get:
x = (-23 ± √(23^2 - 4*12*10))/(2*12)
Simplifying further:
x = (-23 ± √(529 - 480))/(24)
x = (-23 ± √49)/(24)
x = (-23 ± 7)/(24)
Breaking it down:
For the plus sign:
x1 = (-23 + 7)/24 = -16/24 = -2/3
For the minus sign:
x2 = (-23 - 7)/24 = -30/24 = -5/4
So, the solutions of the quadratic equation 12x^2 + 23x + 10 = 0 are x = -2/3 and x = -5/4.
Comparing these solutions with the choices given, we can see that the correct answer is option C: 5/4 and 2/3.