dimension of a floor; the perimeter of a rectangular floor is 90ft. find the dimensions of the floor if the length is twice the width
P = 2L + 2W
90 = 4W + 2W
90 = 6W
15 = W
Check:
15 + 15 + 30 + 30 = 90
i know 90 is the perimeter but where did the 4W + 2W come from?
This is the formula for a perimeter.
P = 2L + 2W
Your problem states that the length is twice the width. Therefore, L = 2W
what happened to 2L? sorry for my dumb question.
oh nevermind.. i got it. thanks for helping me Ms. Sue (:
You're welcome, Sha.
To find the dimensions of a rectangular floor when the perimeter is given, we need to use some algebraic equations. Let's assume the width of the floor as 'w' feet.
According to the given information, the length is twice the width. Therefore, the length will be '2w' feet.
The perimeter of a rectangle is calculated by adding all the sides together, which in this case would be:
P = 2L + 2W
Substituting the given values:
90 = 2(2w) + 2w
Simplifying the equation:
90 = 4w + 2w
90 = 6w
Now, we can solve the equation to find the value of 'w':
w = 90 / 6
w = 15
So, the width of the floor is 15 feet. Since the length is twice the width, the length will be:
2w = 2(15) = 30 feet
Therefore, the dimensions of the floor are 30 feet (length) and 15 feet (width).