I cannot find it in my text book I have a math problem : 2f2 + 9f + 6
for f = 10
The second 2 is to the second power. So with the order of operation do I muliply 2 by 10 first and then 20 the the second power?
Thanks Math is really killing me!
2 f^2 + 9 f + 6
for f = 10
2 (10)(10) + 9 (10) + 6
200 + 90 + 6
296
2(10 . 10) + 9 . 10 + 6
= 2 (100) + 90 + 6
= 200 + 90 + 6
= 296
Oh wow, I had that wrong! Thank you!
To solve the equation 2f^2 + 9f + 6 when f = 10, you need to substitute the value of f into the equation and simplify. Let me walk you through the steps:
Step 1: Substitute the value of f into the equation:
2(10)^2 + 9(10) + 6
Step 2: Simplify the exponent:
2(100) + 9(10) + 6
Step 3: Perform the multiplications:
200 + 90 + 6
Step 4: Add the terms:
296
Therefore, when f = 10, the equation 2f^2 + 9f + 6 equals 296.
Remember, when substituting values into an equation, you should replace the variable with the given value and follow the order of operations (PEMDAS/BODMAS) to simplify the expression.