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An automobile starts from rest and accelerates to a final velocity in two stages along a straight road. Each stage occupies the same amount of time. In stage 1, the magnitude of the car's acceleration is 3.5 m/s2. The magnitude of the car's velocity at the end of stage 2 is 2.9 times greater than it is at the end of stage 1. Find the magnitude of the acceleration in stage 2.

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dd

  1. STage2:

    acceleration= (V2-V1)/T=V1(1.9)/T

    Stage1:

    acceleration= (V1-0)/T
    3.5=V1/T

    So we put V1=3.5T in the first equation..
    acceleartion= 3.5T*1.9/T= 3.5*1.9 m/s^2

    so there you have it.

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    bobpursley

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    Jon

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