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precal
Given that lim x>c f(x)=6 and that lim x>c g(x)= 4, evaluate the following limit. Assume that c is a constant. The x in front of the f is confusing me. lim [xf(x) + 3 g(x)]^2 x>c
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i need some serious help with limits in precalc. here are a few questions that i really do not understand. 1. Evaluate: lim (3x^32x^2+5) x> 1 2. Evaluate: lim [ln(4x+1) x>2 3. Evaluate: lim[cos(pi x/3)] x>2 4. Evaluate:
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Question: If lim(f(x)/x)=5 as x approaches 0, then lim(x^2(f(1/x^2))) as x approaches infinity is equal to (a) 5 (b) 5 (c) infinity (d) 1/5 (e) none of these The answer key says (a) 5. So this is what I know: Since
asked by Anonymous on March 2, 2019 
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How do we evaluate limit of, lim x> 0 [ln(x+1)/( (2^x)  1)] I tried using the substitution x+1 = e^k , when x tends to 0 so does k, which gave out, lim k>0 [ k/((2^((e^k)  1)) 1 ) ] which I simplified into( for the ease of
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asked by . on September 3, 2006 
calc
need to find: lim as x > 0 of 4(e^2x  1) / (e^x 1) Try splitting the limit for the numerator and denominator lim lim x>0 4(e^2x1) (4)x>0 (e^2x1) ______________ = ________________ lim lim x>0 e^X1 x>0 e^x1 Next solve for
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asked by Jane on December 7, 2014 
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Find the limit of the sequence 2ln(1+3n)  ln(4+n^2) What I did: lim as n approach inf of an = 2*lim ln (1+3n)/(4+n^2) = 2 * lim ln (1/n^2 + 3n/n^2) / (4/n^2 + n^2/n^2) = 2 * lim ln (1/n^2 + 3/n) / (4/n^2 + 1) = 2 * lim ln
asked by Helloo on April 25, 2019 
Calculus
Find the indicated limits. If the limit does not exist, so state, or use the symbol + ∞ or  ∞. f(x) = { 2  x if x ≤ 3 { 1 + 3x  x^2 if x > 3 a) lim 3+ f(x) x>3 b) lim 3 f(x) x>3 c) lim f(x) x>3 d) lim ∞ f(x) x>3
asked by Chris on October 9, 2011 
Calculus
Find the indicated limits. If the limit does not exist, so state, or use the symbol + ∞ or  ∞. f(x) = { 2  x if x ≤ 3 { 1 + 3x  x^2 if x > 3 a) lim 3+ f(x) x>3 b) lim 3 f(x) x>3 c) lim f(x) x>3 d) lim ∞ f(x) x>3
asked by Blue on October 8, 2011