NaOH(aq) + HCl(aq)----> H20 + Nacl(aq).. solve for the amoont of energy aborbed by the solution. (50ml of 1.0M HCl is 23deg; 50ml of 1.0M NaOH is at 25deg; mixed solutuion= 31deg

pls tell me the steps to take inorder to solve the question. Thanks in advance.

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  1. Since the T of the acid and base are not the same I would do it in two steps.
    qHCl = mass water x specific heat x (Tfinal-Tinitial).
    qNaOH = mass water x specific heat x (Tfinal-Tinitial).
    Then add qHCl + qNaOH = total q.

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