need help solving
two houses are for sale on the same street.the second house has 1000 square feet less than twice the square feet of the first house. together the houses have 4400 square feet. what is the square footage of the first house?
2x-1000 = 4400 ???
No.
FirstHouse+secondHouse=4400
F+ (2F-1000)=4400
3F-1000=4400
I don't understand how you solved this problem
To solve this problem, let's set up an equation.
Let's represent the square footage of the first house as "x". According to the information given, the second house has 1000 square feet less than twice the square footage of the first house.
So, the square footage of the second house can be represented as "2x - 1000".
The total square footage of both houses is given as 4400 square feet. So, we can write the equation as:
x + (2x - 1000) = 4400
Now, let's solve for x:
Combine like terms:
3x - 1000 = 4400
Add 1000 to both sides:
3x = 5400
Divide both sides by 3:
x = 1800
Therefore, the square footage of the first house is 1800 square feet.
I don't understand how you solved this problem
Let F stand for the area of the first house. Then 2F - 1000 = area for the second house. Both of those together = 4400.
Thus F + (2F -1000) = 4400
Does that help?