How much water at 25 degrees celsius is needed to dissolve 10 grams of baruim phosphate?
Ba3(PO4)2 ==> 3Ba^+2 + 2PO4^-3
Set up Ksp chart, find solubility from Ksp which will be in moles/L. Convert that to grams to give you g/L, then determine the amount of water necessaary to dissolve 10 g.
the Ksp of barium phosphate is 1.3996*10^-8 how much water would you need to to dissolve this amount of baruim phospahte?
the molar solubilty of baruim phosphate is 8.42335*10^-6 g/L
what formula would i use to figure out the water?
Don't you know how to calculate the solubility of Ba3(PO4)2?
Ba3(PO4)2 ==> 3Ba^+3 + 2PO4^-3
Ksp = (Ba^+2)^3(PO4^-3)^2
If you let S = solubility of Ba3(PO4)2, then (Ba^+2) = 3S and (PO4^-3) = 2S.
Substitute 3S and 2S in the Ksp expression to obtain
(3S)^3(2S)^2 = Ksp.
Solve for S which tells you the solubility of the compound in moles/L.
Convert that to grams/L THEN you can work on how much water would be necessary to dissolve 10 g. I didn't work it out but I expect a bunch. By the way, post your work if you get stuck. This much is a freebie for you.
To calculate the amount of water needed to dissolve a certain mass of a substance, we need to know the solubility of the substance in water. The solubility is usually given in grams of the substance that can dissolve in 100 grams of water at a specific temperature. However, it's important to note that not all substances have defined solubilities at all temperatures.
In this case, to determine the amount of water needed to dissolve 10 grams of barium phosphate, we need to know the solubility of barium phosphate at 25 degrees Celsius.
Let's assume that the solubility of barium phosphate at 25 degrees Celsius is given as 5 grams per 100 grams of water.
Now, we can set up a proportion using the mass of barium phosphate we want to dissolve (10 grams) and the solubility:
(10 grams of barium phosphate) / (5 grams of barium phosphate) = (x grams of water) / (100 grams of water)
Cross-multiplying, we get:
10 grams of barium phosphate * 100 grams of water = 5 grams of barium phosphate * x grams of water
1000 grams of water = 5x grams of water
Dividing both sides by 5, we find that:
x grams of water = 1000 grams of water / 5
x grams of water = 200 grams of water
So, to dissolve 10 grams of barium phosphate at 25 degrees Celsius, you would need approximately 200 grams of water.