two numbers are reciprocals of each other and one of them is four times as large as the other. what are the two numbers?
n= 4(1/N)
n(n)=4
n=-+2
so we have 2,1/2 as the numbers, or -2, -1/2 as the numbers.
thanks....I haven't even been shown that way to figure it out. Thanks so much!
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What. Do you do differently to solve these two subtraction problems
To solve this problem, let's assign variables to the two numbers. Let's say the first number is x, and the second number is y.
We are given two pieces of information:
1. Two numbers are reciprocals of each other: This means that if we multiply the two numbers together, we will get 1. So, we have the equation: x * y = 1.
2. One number is four times as large as the other: This means that if we multiply one of the numbers by 4, we will get the other number. So, we have the equation: x = 4y.
Now, we can solve these two equations simultaneously to find the values of x and y.
Let's substitute the value of x from equation 2 into equation 1:
(4y) * y = 1
4y^2 = 1
y^2 = 1/4
y = √(1/4) or y = -√(1/4)
Since y is the reciprocal of x, we can conclude that if y is √(1/4), then x is the reciprocal of y, which is (√(1/4))^(-1), or 2. Similarly, if y is -√(1/4), x is 2.
Therefore, the two numbers are (2, √(1/4)) or (2, -√(1/4)).