How much would 3.45* 10^21 C12H22 O11 molecules weigh
6.02 x 10^23 molecules of C12H22O11 have a mass of the molar mass.
To calculate the weight of 3.45 * 10^21 C12H22O11 molecules, we need to know the molar mass of C12H22O11.
The molar mass of a compound is the sum of the molar masses of all the elements in its chemical formula. To calculate the molar mass of C12H22O11, we need to look up the molar masses of carbon (C), hydrogen (H), and oxygen (O) from the periodic table.
The molar mass of carbon (C) is approximately 12.01 g/mol.
The molar mass of hydrogen (H) is approximately 1.008 g/mol.
The molar mass of oxygen (O) is approximately 16.00 g/mol.
Next, we multiply the number of each element in the chemical formula by its molar mass and sum them up.
C12H22O11 has:
- 12 carbon atoms, so the mass of carbon is 12 * 12.01 g/mol.
- 22 hydrogen atoms, so the mass of hydrogen is 22 * 1.008 g/mol.
- 11 oxygen atoms, so the mass of oxygen is 11 * 16.00 g/mol.
Now, we can calculate the molar mass of C12H22O11 by adding up the individual masses:
Molar mass of C12H22O11 = (12 * 12.01) + (22 * 1.008) + (11 * 16.00) g/mol.
Once we have the molar mass, we can calculate the weight of 3.45 * 10^21 C12H22O11 molecules.
First, convert the given number of molecules to moles by dividing by Avogadro's number (6.022 * 10^23 molecules/mol):
Number of moles = (3.45 * 10^21 molecules) / (6.022 * 10^23 molecules/mol).
Finally, multiply the number of moles by the molar mass to get the weight:
Weight = Number of moles * Molar mass.
By following these steps, you should be able to calculate the weight of 3.45 * 10^21 C12H22O11 molecules.