If x + 3/2 is an integer, then x must be what
a fraction
ms sue the answer choices does not include fraction it has to be an integer even or odd
Ahh -- I see now. You had written it in such a way that it could be interpreted more than one way.
The correct way to write your problem (as you explained in a later post) is:
(x + 3)/ 2 =
Thanks Ms. Sue
If (x + 3)/2 is an integer, then x must be what
I answered it in your later post about this question.
To determine what x must be if x + 3/2 is an integer, we need to understand the concept of integers and how they relate to fractions.
The set of integers includes all positive and negative whole numbers, as well as zero: {..., -3, -2, -1, 0, 1, 2, 3, ...}. Fractions, on the other hand, represent parts of a whole and have the form a/b, where a is the numerator and b is the denominator.
In this case, we have the expression x + 3/2. For this expression to be an integer, the sum of x and 3/2 must yield a whole number.
To convert the fraction 3/2 into an integer, we can rewrite it as 3/2 = 1 + 1/2. Therefore, x + 3/2 can be written as x + 1 + 1/2.
To simplify the expression, we can combine the integers, so x + 1 + 1/2 becomes x + 3/2. Now, the expression can be written as x + 3/2.
To make x + 3/2 an integer, the fractional part (3/2) needs to be eliminated. This can be achieved by choosing an x such that the numerator becomes a multiple of the denominator (2). In other words, x must be an integer that yields an integer result when added to 3/2.
For example, if we choose x = 1, then x + 3/2 = 1 + 3/2 = 3/2 + 3/2 = 6/2 = 3, which is an integer. Similarly, if we choose x = 2, then x + 3/2 = 2 + 3/2 = 4/2 + 3/2 = 7/2 = 3.5, which is not an integer.
Therefore, x must be an integer value that satisfies the condition x + 3/2 = an integer.