Verify the following identity
2 tan x/1+tan^2 x = sin 2x
One of the variations of sin^x + cos^x = 1 is
1 + tan^2x = sec^2x
so
LS = [2(sinx/cosx)]/sec^2x
= (2sinx/cosx)(1/cos^2x)
= 2sinxcosx
= sin 2x
= RS
2 tan x/1+tan^2 x = sin 2x
1 + tan^2x = sec^2x
so
LS = [2(sinx/cosx)]/sec^2x
= (2sinx/cosx)(1/cos^2x)
= 2sinxcosx
= sin 2x
= RS