x+3y=6
I did it like x + 3y = 6
____________
x*(-1) +3*(2) ?6
-1 6
-6
Also, (-1,2) intercepts (3,6)
Am I correct. If so. then
solution for x = -1
I have no idea what the question is, nor what you did.
y intercept is when x = 0
0 + 3y = 6
y = 2
so (0,2)
x intercept is when y = 0
x + 0 = 6
x = 6
so (6,0)
If x = -1 then
-1 +3y = 6
3 y = 7
y = 7/3
Based on your calculations, you have solved for one possible solution to the equation x + 3y = 6. However, your method seems unclear. Let's go through a more detailed explanation of how to solve this equation.
To find the solution for x, we need to isolate the variable x on one side of the equation. Here's the step-by-step process:
1. Start with the equation: x + 3y = 6
2. Subtract 3y from both sides of the equation to move terms involving y to the opposite side:
x = 6 - 3y
3. Now we have x isolated on one side of the equation. We can find the solution for x by plugging in a particular value for y. Let's use the value y = 2 as you mentioned in your explanation.
4. Substitute y = 2 into the equation: x = 6 - 3(2)
x = 6 - 6
x = 0
So, when y = 2, the solution for x is 0. Therefore, the solution to the equation x + 3y = 6 is x = 0.
Regarding your comment about intercepts, the intercepts of an equation are the points where the graph of the equation crosses the x-axis or the y-axis. In this case, the intercepts can be found by setting x or y to 0 and solving for the other variable.
To find the x-intercept, set y = 0 and solve for x:
x + 3(0) = 6
x = 6
Therefore, the x-intercept is (6, 0).
To find the y-intercept, set x = 0 and solve for y:
0 + 3y = 6
3y = 6
y = 2
Therefore, the y-intercept is (0, 2).
In summary, the solution for x in the equation x + 3y = 6 is x = 0. The intercepts are (6, 0) and (0, 2).