If 0.433 mol of gaseous CS2 and 1.62 mol of gaseous H2 are reacted according to the balanced equation at 454 K and in a 40.0 L vessel, what partial pressure (atm) of gaseous CH4 is produced?
CS2(g) + 4H2(g) -> CH4(g) + 2H2S(g)
Molar Mass (g/mol)
CS2 76.143
H2 2.016
CH4 16.043
figure the moles of the reactants first. THen determine the limiting reageant (CS2). THen determine the moles of methane (.443) produced.
partial pressure=molesmethane*RT/40
Remember that there is still H2 left over, and it will have a partial pressure also, as will the H2S produced, all add to total pressure if you have to calculate that.
I tried the method that you provided above and the grading system told me that the answer was wrong. The correct answer is (0.3775). Do you know how to come up with that answer?
To find the partial pressure of gaseous CH4 produced, we first need to calculate the number of moles of CH4 formed based on the balanced equation.
From the balanced equation, we can see that 1 mol of CS2 reacts with 4 mol of H2 to form 1 mol of CH4.
So, for 0.433 mol of CS2, we would need 4 * 0.433 mol of H2 to react completely. Therefore, the number of moles of H2 used is 1.732 mol (4 * 0.433).
Now, let's calculate the number of moles of CH4 formed. Since the ratio of moles of CS2 to moles of CH4 is 1:1, we can say that 0.433 mol of CH4 would be formed as well.
To convert the moles of CH4 to partial pressure in atm, we can use the Ideal Gas Law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.
First, let's convert the given volume to liters. The volume is stated as 40.0 L, which is already in liters.
Now, we can substitute the known values into the Ideal Gas Law equation to solve for the pressure (P) of CH4:
P * V = n * R * T
P * 40.0 L = 0.433 mol * (0.0821 L * atm/mol * K) * 454 K
Simplifying the equation, we have:
P = (0.433 * 0.0821 * 454) / 40.0
Solving the equation, we get:
P ≈ 2.25 atm
Therefore, the partial pressure of gaseous CH4 produced is approximately 2.25 atm.