Thank you for any help and assistance.
Here is the question/problem:
Because of the pressure inside a popcorn kernel, water does not vaporize at 100 degrees Celsius. Instead, it stays liquid until its temperature is about 175 degrees Celsius, at which point the kernel ruptures and the superheated water turns into steam. How much energy is needed to pop 95.0 grams of corn if 14 percent of a kernel's mass consists of water? Assume that the latent heat of vaporization for water at 175 degrees Celsius is 0.90 times its value at 100 degrees Celsius and that the kernels have an initial temperature of 175 degrees Celsius.
heat=mass*Lv where mass is 95*.14 gramsposted by bobpursley