find the two ordered pairs of this equation.
y=5/3x+8
then give the slope and y intercept.
I know the slope is rise over run and is the y intercept 8?
Your Y-Intercept is 8. From there on the graph you'd go to Positve 8 and from there you'd either go 5 up and 3 to the right or 5 down and 3 to the left....Either one would give you points on a straight line.
To find the ordered pairs, you need to plug in different values of x into the equation and solve for y. Let's choose two different values of x and find the corresponding y values:
Ordered Pair 1: Let's set x = 0.
Substituting x = 0 into the equation:
y = (5/3)(0) + 8
y = 0 + 8
y = 8
So, the first ordered pair is (0, 8).
Ordered Pair 2: Let's set x = 3.
Substituting x = 3 into the equation:
y = (5/3)(3) + 8
y = 5 + 8
y = 13
So, the second ordered pair is (3, 13).
Now, let's discuss the slope and y-intercept:
The slope of the equation y = (5/3)x + 8 is the coefficient of x, which is 5/3. The slope represents the rate of change of y with respect to x. In this case, for every increase of 1 in x, y increases by 5/3.
The y-intercept is the value of y when x = 0. In this equation, the y-intercept is 8 because when x = 0, y = 8. The y-intercept is the constant term in the equation.
So, the slope is 5/3 and the y-intercept is 8.