how many grams of solute are in 250ml of 0.500M glycerin . (C3H8O3=92.1 amu)?
M = moles/L
You know M and you know L, calculate moles.
Then moles = grams/molar mass.
You know moles and molar mass, calculate moles.
To calculate the number of grams of solute in 250 mL of 0.500M glycerin, you need to use the formula:
grams of solute = (concentration in M) × (volume in L) × (molar mass)
First, convert the volume from milliliters (mL) to liters (L):
250 mL ÷ 1000 mL/L = 0.250 L
Now calculate the grams of solute using the given information:
grams of solute = (0.500 M) × (0.250 L) × (92.1 g/mol)
grams of solute = 11.525 g
To determine the number of grams of solute in a solution, you need to use the equation:
moles = concentration (M) x volume (L)
1. First, convert the volume from milliliters (ml) to liters (L):
250 ml = 0.25 L
2. Next, use the given molarity (M) to calculate the number of moles:
moles = 0.500 M x 0.25 L
3. Now you have the number of moles. To find the grams of solute, you need to multiply the moles by the molar mass of glycerin (C3H8O3):
molar mass of glycerin (C3H8O3) = 3(12.01 amu) + 8(1.01 amu) + 3(16.00 amu)
molar mass of glycerin (C3H8O3) = 92.1 amu
grams of solute = moles x molar mass
grams of solute = moles x 92.1 amu
Therefore, the number of grams of glycerin in 250 ml of 0.500M glycerin is given by:
grams of solute = (0.500 M x 0.25 L) x 92.1 amu