Most natural gas consists of about 90% methane, CH4. Assume that the solubility of natural gas at 20 C and 1 atm gas pressure is about the same as that of CH4, 0.02 g/kg water. If a sample of natural gas under a pressure of 20 atm is kept in contact with 1.00 *10^3 kg of water, what mass of natural gas will disolve

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To find the mass of natural gas that will dissolve in the given amount of water, we can use the solubility of CH4 in water.

Given:
Pressure of natural gas = 20 atm
Solubility of CH4 in water at 20°C and 1 atm = 0.02 g/kg water
Mass of water = 1.00 * 10^3 kg

First, let's convert the pressure of natural gas from atm to kg/cm² using the conversion:
1 atm = 1.01325 kg/cm²

Pressure of natural gas = 20 atm * 1.01325 kg/cm²/atm
Pressure of natural gas = 20.265 kg/cm²

Now, let's calculate the mass of natural gas that will dissolve in the given water:

Mass of natural gas = solubility of CH4 * mass of water

Mass of natural gas = 0.02 g/kg * 1.00 * 10^3 kg
Mass of natural gas = 20 g

Therefore, the mass of natural gas that will dissolve is 20 grams.

To calculate the mass of natural gas that will dissolve in water, we need to use Henry's Law, which states that the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid.

First, we need to convert the given pressure of 20 atm into the corresponding partial pressure of CH4. Since CH4 makes up about 90% of natural gas, we can assume that the partial pressure of CH4 is also 90% of the total pressure.

Partial Pressure of CH4 = 90% of 20 atm = 0.9 * 20 atm = 18 atm

Next, we can use the solubility of CH4 in water to calculate the mass of dissolved CH4.

Solubility of CH4 = 0.02 g/kg water

Mass of water = 1.00 *10^3 kg

Mass of CH4 dissolved = Solubility of CH4 * Mass of water

Mass of CH4 dissolved = 0.02 g/kg * 1.00 *10^3 kg

Mass of CH4 dissolved = 20 g

So, the mass of natural gas (CH4) that will dissolve in the given sample of water is 20 grams.