calculus

suppose that the area under the curve y=1/x from x=a to x=b is k. the area in terms of k, under the curve y=1/x from x=2a to x=2b? justify

asked by Anonymous
  1. INt x^-1= lnx or k= ln(b/a)

    so from 2a to 2b, areas is ln(2b/2a)= k

    posted by bobpursley

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