A 63-kg bungee jumper has fallen far enough that her bungee cord is beginning to stretch and resist her downward motion. Find the force (magnitude and direction) exerted on her by the bungee cord at an instant when her downward acceleration has a magnitude of 8.4 m/s2. Ignore the effects of air resistance.
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88.2N and UP
To find the force exerted on the bungee jumper by the bungee cord, we can use Newton's second law of motion, which states that the force exerted on an object is equal to the mass of the object multiplied by its acceleration. The direction of the force will be opposite to the direction of the acceleration.
Given:
Mass of the bungee jumper, m = 63 kg
Acceleration, a = 8.4 m/s²
We can use the formula:
Force = mass × acceleration
Substituting the given values:
Force = 63 kg × 8.4 m/s²
Calculating the force:
Force = 529.2 N
Therefore, the magnitude of the force exerted on the bungee jumper by the bungee cord is 529.2 N. Since the acceleration is in the downward direction, the force exerted by the bungee cord will be in the upward direction (opposite to the acceleration).